Reg Ex
Some more regular expression. And what for? To make BIG numbers more readable. For Example instead of 1234567 Euro we want to have 1’234’567 Euro. Wayyy better. So let’s write a helper method with a regex! Thanks to Arne we got it finally working:
def format_large_number(number)
number.to_s.gsub(/\D/, '').reverse.gsub(/.{3}/, '\0\'').reverse.gsub(/^\'/, '')
end
The method takes the number and:
- substitutes everything that’s not a number with nothing
- reverses the number (7654321)
- takes that and puts a ‘ every third position (765’432’1)
- and reverses it again (1’234’567)
- and in case we have a ‘ in the beginning, it substitutes it with nothing so we don’t get a ‘123’456
Piepe einfach (which translates as: easy peasy)
(Arne: In case I bungled the explanation, please contact me!)
